Exercise: Binary Tree Post-order II labuladong Original About 12271 words
663. 均匀树划分 https://leetcode.cn/problems/equal-tree-partition 663. Equal Tree Partition https://leetcode.com/problems/equal-tree-partition 687. 最长同值路径 https://leetcode.cn/problems/longest-univalue-path 687. Longest Univalue Path https://leetcode.com/problems/longest-univalue-path 865. 具有所有最深节点的最小子树 https://leetcode.cn/problems/smallest-subtree-with-all-the-deepest-nodes 865. Smallest Subtree with all the Deepest Nodes https://leetcode.com/problems/smallest-subtree-with-all-the-deepest-nodes 1026. 节点与其祖先之间的最大差值 https://leetcode.cn/problems/maximum-difference-between-node-and-ancestor 1026. Maximum Difference Between Node and Ancestor https://leetcode.com/problems/maximum-difference-between-node-and-ancestor 1120. 子树的最大平均值 https://leetcode.cn/problems/maximum-average-subtree 1120. Maximum Average Subtree https://leetcode.com/problems/maximum-average-subtree 1339. 分裂二叉树的最大乘积 https://leetcode.cn/problems/maximum-product-of-splitted-binary-tree 1339. Maximum Product of Splitted Binary Tree https://leetcode.com/problems/maximum-product-of-splitted-binary-tree 1372. 二叉树中的最长交错路径 https://leetcode.cn/problems/longest-zigzag-path-in-a-binary-tree 1372. Longest ZigZag Path in a Binary Tree https://leetcode.com/problems/longest-zigzag-path-in-a-binary-tree 1245. 树的直径 https://leetcode.cn/problems/tree-diameter 1245. Tree Diameter https://leetcode.com/problems/tree-diameter 606. 根据二叉树创建字符串 https://leetcode.cn/problems/construct-string-from-binary-tree 606. Construct String from Binary Tree https://leetcode.com/problems/construct-string-from-binary-tree 1443. 收集树上所有苹果的最少时间 https://leetcode.cn/problems/minimum-time-to-collect-all-apples-in-a-tree 1443. Minimum Time to Collect All Apples in a Tree https://leetcode.com/problems/minimum-time-to-collect-all-apples-in-a-tree Prerequisites
Before reading this article, you should first learn:
Basic binary tree functions like summing values or calculating height are easy to write. Sometimes, simply adding a bit of code at their post-order position can give us the desired result.
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Exercise: Binary Tree Post-order I
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Exercise: Binary Tree Post-order III